![]() Because finding the square root of a negative number is impossible, we know that no x intercepts exist for this particular parabola.Our previous standard form example, 2x 2 + 16x + 39 gets plugged into the quadratic formula as follows:. ![]() The parabola's x intercepts are at approximately x = -1.318 and 1.518 -5x 2 + 1x + 10 gets plugged into the quadratic formula as follows:.X Research source Note that this often gives you two answers for x, which is OK - this just means your parabola has two x intercepts. If it isn't already, get your equation into the form ax 2 + bx + c, then plug a, b, and c into the formula x = (-b +/- SqRt(b 2 - 4ac))/2a. X Research source If you can't easily solve for your x intercepts or factor your equation, use a special equation called the quadratic formula designed for this very purpose. In this case, your only x intercept is -1 because setting x equal to -1 will make either of the factored terms in parentheses equal 0.In this case, your x intercepts are the values for x which make either term in parentheses = 0. Some equations in the ax 2 + bx + c form can be easily factored into the form (dx + e)(fx +g), where dx × fx = ax 2, (dx × g + fx × e) = bx, and e × g = c. x = 11 and 13 are the parabola's x-intercepts. This method may work for simple quadratic equations, especially in vertex form, but will prove exceedingly difficult for more complicated ones. Simply set f(x) = 0 and solve the equation. ![]() Otherwise, solve for your x intercepts with one of the following methods: If your parabola has a vertex opens upward and has a vertex above the x axis or if it opens downward and has a vertex below the x axis, it won't have any x intercepts. However, not all parabolas have x-intercepts. Even if you're not to find them, these two points can be invaluable for drawing an accurate parabola. X Research source Often, on schoolwork, you'll be asked to find a parabola's x-intercepts (which are either one or two points where the parabola meets the x axis). If necessary, find and plot x intercepts. The coordinates of the vertex in standard form are given by: h = -b/2a and k = f(h), while in vertex form, h and k are specified in the equation.
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